Question
Two wires of the metal have the same length but their crosssections are in the ratio $3: 1$ They are joined in series: The resistance of the thicker wire is $10 \Omega$. The total resistance of the combination will be(A) 40(B) $(40 / 3)$(C) $(5 / 2)$(D) 100
Step 1
Step 1: The resistance of a wire is given by the formula $R = \rho \frac{l}{A}$, where $\rho$ is the resistivity of the material, $l$ is the length of the wire, and $A$ is the cross-sectional area of the wire. Show more…
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Two wires of same metal have same length but their cross-sections are in the ratio $3: 1$. They are joined in series. The resistance of the thicker wire is $10 \Omega$. The total resistance of the combination will be (a) $(5 / 2) \Omega$ (b) $(40 / 3) \Omega$ (c) $40 \Omega$ (d) $100 \Omega$
Two wires of same metal have same length but their cross-sections are in the ratio 3 : 1. They are joined in series. The resistance of the thicker wire is 10 Ω. The total resistance of the combination will be
Two wires of same metal have the same length but their cross-sections area in the ratio 3 : 1. They are joined in series. The resistance of the thicker wire is 10? .The total resistance of the combination will be:
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