Question
UK wiring regulations specify a maximum current of $13 \mathrm{~A}$ in 1.5-mm $^{2}$ cross-sectional area copper wire. What's the corresponding current density?
Step 1
We know that 1 mm$^2$ = $10^{-6}$ m$^2$. So, the cross-sectional area A = 1.5 mm$^2$ = 1.5 $\times 10^{-6}$ m$^2$. Show more…
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