2 \times 10^{5} \mathrm{~m/s}$, and the work function of the material, $\phi = 3.44 \mathrm{~eV}$. We can use the photoelectric effect equation to find the frequency of the incident light:
\[
KE_{max} = hf - \phi
\]
where $KE_{max}$ is the maximum kinetic energy
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