00:01
One method for removing sulfur dioxide from the flu gases of power plants involves reaction with aqueous hydrogen sulfide.
00:12
Elemental sulfur is the product.
00:14
Part a asks us to write the reaction.
00:19
And actually there are two.
00:22
So let's begin.
00:26
Each of these has a different form of hydrogen in them.
00:32
Just a sec to get back to my problem.
00:50
Okay, this equation is the equation i'm going to use for the rest of the calculations.
01:16
There's our first equation, and again, our second equation just has a different form of sulfur as a product.
01:53
Okay, so there's my two answers for part a.
02:03
Let's get ready for part b.
02:06
Part b.
02:10
What volume of h2s at 27 degrees celsius, which is 300 .15k, and 740 tor, which is 740 divided by 760? and i think that was, i wrote it down here.
02:42
Hang on, i closed my book by mistake.
02:50
737.
03:01
Okay, would we be required to remove the so2 that is formed by burning one ton of coal with 3 .5 % sulfur by mass? okay, let's start this by figuring out how much we have here.
04:01
So we have 2 ,000.
04:03
Pounds is a ton and we from a previous problem knew that there are 453 .6 grams per ton and we know that there's 32 .06 grams of sulfur per mole and we knew that this was 0 .0355 percent.
04:45
Let me punch the numbers into the calculator.
05:00
We get 990 .4.
05:12
Okay in s02 there's one s we've got a one -to -one relationship so that gives me 990 and now we can do our conversion our first conversion and if we look at our equations we can see that's a two and a one and then we'll multiply that by 22 .4 liters per mole in here let me verify this no, i didn't do it.
06:28
It's not at standard pressure, so i didn't do this...