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Good day.
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The topic is about colligative properties.
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When solute is dissolved in solvent, the properties of the solution that is formed are different from the properties of the pure solvent.
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In particular, the solution freezes at a lower temperature than that of the pure solvent.
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When a non -electroletic solute, that is a solute that doesn't dissolve into ion, at the same time, a non -volatile solute that is a solute that doesn't evaporate, is dissolved in solvent, then the solution that is formed freezes according to the following equation.
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Tf of the solution is equal to tf of the solvent minus kf times m, where kf is the freezing point constant and which value depends on the solvent that is used, and m is the molality of the solution.
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Now let us consider a solution that is formed using a certain mass of sucrose dissolved in 725 kilograms.
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Grams or rather grams of water we don't know the mass of the sucrose in fact it's the one that we're looking for and the mass of water is given to be 725 water here stands as the solvent it was found out that the solution formed from these freezes at a temperature of negative 1 .85 degrees celsius now we wish to find the mass of the sucrose that is added so we will start by first finding the molality of the solution.
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So using the formula above, we have tf solution, tf solvent minus kf times m.
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We note the tf of the solution is given to be negative 1 .85.
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And that of the solvent, which is water, is zero.
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Since we know water freezes at zero degree celsius under normal atmospheric condition, we will be able to solve for kf, or rather, m, but of course we note that kf for water is 1 .86.
02:26
We can search this up from several sources.
02:30
So we have negative 1 .85 equals 0 minus 1 .86 times m.
02:38
And this gives us negative 1 .85 over negative 1 .86 or this is equal to 1 .1...