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Unless otherwise stated, the lens-to-retina distance is 2.00 cm.

People who do very detailed work close up, such as jewellers, often can see objects clearly at much closer distance than the normal 25 cm.

(a) What is the power of the eyes of a woman who can see an object clearly at a distance of only 8.00 cm?(b) What is the size of an image of a 1.00 mm object, such as lettering inside a ring, held at this distance?(c) What would the size of the image be if the object were held at the normal 25.0 cm distance?

a. $+62.5 \mathrm{D}$b. $-0.25 \mathrm{mm}$c. $-0.08 \mathrm{mm}$

Physics 103

Chapter 26

Vision and Optical Instruments

Reflection and Refraction of Light

Wave Optics

Cornell University

Simon Fraser University

University of Winnipeg

Lectures

02:51

In physics, wave optics is…

02:30

In optics, ray optics is a…

01:24

Suppose the distance from …

. The focal length of a si…

02:36

The focal length of a simp…

00:47

Unless otherwise stated, t…

02:02

Lens-retina distance Assum…

02:50

The near point of a person…

02:04

02:19

A jeweler’s lens of focal …

01:37

02:16

Eye The image distance for…

03:51

(II) A person's right…

04:14

The near point of an eye i…

05:09

A microscope has an eyepie…

01:50

01:59

Unless the problem states …

08:54

An object is located at $x…

03:34

02:58

A thin lens with a focal l…

02:03

A microscope has an object…

05:50

An object is placed in fro…

power off the eyes off The woman is given by peasy. Call to this is for a off the problem. P e Z called the one more distance of the object plus one or distance to the image substrate in the values from the even problem we have distressed to the object three heavies, 0.8 meters close Distance to the image we have is broken 02 meters. So it's simple. Find this expression gives us the power off the eyes off The woman is plus 62 +15 years in Barbie, we were asked to find the height of the image When an object is placed it eight centimeter So hide off the image. Divide my height off The object is equal to minus distance the image divide by distance to the object. From here we can find a chai that is a quantity minus eternal Lord d I derided I d note substituting the values we have on minus one millimeter times. So this is one minus one. Um, to sending me Did you ever eight centimeter centimeter simplifying despues or some minus zero point to fly school millimeter. This is the height of the image. So we're again in party. Asked to find the height of the image for the object which is placed it a 25. Uh, sending me just then we can use the same form right here. We'll do the substitution. Medically, that's one 1,000,000. Return to divide by 25. It's in kind. This expression used 0.0 beat. Really? Uh, this is meters. Let me check. This is in meters or little meeting. This is millimeters.

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