00:01
So for this problem, we have a light ray incident on a plane mirror, and it's being reflected.
00:08
It's being refracted and reflected.
00:12
So this is a beam of light that goes through.
00:14
This is a 90 degree angle because the refracted and reflected light rays are perpendicular to each other.
00:23
So we're going to call this angle theta 1, this angle theta 3, and this angle theta 2.
00:35
So first thing we're going to notice is we can use our standard equation of refraction, say n1, sine of theta 1, is equal to n2, sine of theta 1.
00:51
This is equal to 1 because the outside medium in the vacuum, and this is just equal to n because that is what we are given in the problem.
01:00
So now we can say that sine of theta 1 is equal to n sine of theta 1 is equal to n sine of 3.
01:05
Theta 2.
01:06
And we'll note that we can do some geometry to put theta 2 in terms of theta 3.
01:14
And theta 3, of course, is equal to theta 1, because that is the law of reflection on a smooth surface...