Question
Unpolarized light with intensity $I_0$ is incident on two polarizing filters. The axis of the first filter makes an angle of 60.0$^\circ$ with the vertical, and the axis of the second filter is horizontal. What is the intensity of the light after it has passed through the second filter?
Step 1
Here, the light is initially unpolarized, so we take the average over all possible polarization directions, which gives a factor of 1/2. Therefore, the intensity after the first polarizer is $I_1 = I_0 \cos^2(60^\circ)/2 = I_0/4$. Show more…
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Unpolarized light with intensity I0 is incident on two polarizing filters. The axis of the first filter makes an angle of 60.0 with the vertical, and the axis of the second filter is horizontal. What is the intensity of the light after it has passed through the second filter?
Unpolarized light with intensity I0 is incident on two polarizing filters. The axis of the first filter makes an angle of 60.0° with the vertical, and the axis of the second filter is horizontal. What is the intensity of the light after it has passed through the second filter?
Unpolarized light of intensity 20.0 $\mathrm {W/cm}^2$ is incident on two polarizing filters. The axis of the first filter is at an angle of 25.0$^\circ$ counterclockwise from the vertical (viewed in the direction the light is traveling), and the axis of the second filter is at 62.0$^\circ$ counterclockwise from the vertical. What is the intensity of the light after it has passed through the second polarizer?
The Nature and Propagation of Light
Polarization
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