00:01
Hello, so here we're giving it 47 % of adults in 2017, always or often re -nutrition labels.
00:08
So we have p -hat here is 0 .47, and we're giving that n is equal to 1 ,019.
00:15
So in a, we want to do the comp.
00:16
The standard error is the square root of p -hat times 1 minus p -hat over n.
00:21
So we get that our standard error is going to be equal to 0 .47 times 1 -0 -4 -7, times 0 .53 and then divided by 1 ,019.
00:35
And then taking the square root gives us 0 .083.
00:41
So then the limits of the 95 % confidence interval is going to be equal to 0 .47 plus or minus 1 .96 times the standard error.
00:53
And then we get our lower limit here as 0 .26, or 0 .2969.
01:05
And then the upper limit is going to be 0 .631.
01:11
And then for part b, we want to the width of the 95 % confidence interval is going to be equal to the upper limit minus the lower limit.
01:21
So therefore, the width is 0 .3462.
01:26
And then for part c, we want to name a confidence level wider than the 95 % confidence interval.
01:35
So the 99 % confidence interval, the 99 % confidence interval, level provides a wider interval as compared to 95 % because this conference interval is wider as the z critical value for 99 % confidence level is 2 .56, which is greater than the z value of the 95 % level, which is 1 .96...