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Use a calculator or computer to make a table of v…

06:56

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Problem 15 Easy Difficulty

Use a calculator or computer to make a table of values of right Riemann sums $ R_n $ for the integral
$ \int^{\pi}_0 \sin x \, dx $ with $ n $ = 5, 10, 50, and 100. What value do these numbers appear to be approaching?


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Mutahar Mehkri
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00:02

Frank Lin

Related Courses

Calculus 1 / AB

Calculus: Early Transcendentals

Chapter 5

Integrals

Section 2

The Definite Integral

Related Topics

Integrals

Integration

Discussion

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GM

Gazal M.

December 5, 2020

Pls do these problems. I am not paying for you to tell me to look at problem 1 for all of these problems. It's not helping! I want my money back! This is useless! Frank WTF???

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In mathematics, an indefinite integral is an integral whose integrand is not known in terms of elementary functions. An indefinite integral is usually encountered when integrating functions that are not elementary functions themselves.

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In mathematics, integration is one of the two main operations of calculus, with its inverse operation, differentiation, being the other. Given a function of a real variable (often called "the integrand"), an antiderivative is a function whose derivative is the given function. The area under a real-valued function of a real variable is the integral of the function, provided it is defined on a closed interval around a given point. It is a basic result of calculus that an antiderivative always exists, and is equal to the original function evaluated at the upper limit of integration.

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Watch More Solved Questions in Chapter 5

Problem 1
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Problem 4
Problem 5
Problem 6
Problem 7
Problem 8
Problem 9
Problem 10
Problem 11
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Problem 14
Problem 15
Problem 16
Problem 17
Problem 18
Problem 19
Problem 20
Problem 21
Problem 22
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Problem 24
Problem 25
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Problem 27
Problem 28
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Problem 31
Problem 32
Problem 33
Problem 34
Problem 35
Problem 36
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Problem 38
Problem 39
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Problem 41
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Problem 45
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Problem 47
Problem 48
Problem 49
Problem 50
Problem 51
Problem 52
Problem 53
Problem 54
Problem 55
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Problem 61
Problem 62
Problem 63
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Problem 74
Problem 75

Video Transcript

All right, We've got a question here. We've got the integral from zero. Hi, Synnex. Respect to Thanks. All right. And we want to use remind song to determine this value. We also want to use a computer and 75 10, 1500 And see what these values appear to be approaching a number of these values preparing people. All right, So we can start off by taking the endpoints of our sub interval. Start off with setting an equal to five, and we know it would be from zero and five. So you're changing X. Mhm. Excuse me. Zero umpires. You change it, Actually, pi minus 05 Fireworks. Fireflies. All right, so then your x of one is pi over five. And then your exit, too. Hi. See the two pi five. And it just goes on so on and so forth until you get to or accept. Yeah, if I was just £5 or five, which is just pie. All right. Here. What we're gonna do is we're gonna look too, get our mid points. So we see our mid points would be for first region from zero. You know, execute zero and pi or five, which would be pi over 10. And then we would have our midpoint from hire five and two pi over five. Which is the same thing has you can use my handy dandy captain contribute three piles attack and then you just go on and so on and so forth. So you calculate all your limit, you're midpoint values, okay? And then you can go ahead and solve for your Raymond some by taking the taking. The stylist is acting up right now. Okay. Seems to be working, so we would take our agreements down by taking it will change in X multiplied by the function of X sub one, the mid point of the you can accept one midpoint. So basically, you're looking at the values between zero and pie Oh five. And you go on and do the add to this up until you get to the point where you have the midpoint for your last Southern rule. This is just to clarify and write it all out. So it's a little bit more clearer is you're taking your change in X, which is pyro five, and you're just multiplying it by the mid mid point between this region I overturn. What's the midpoint between this region? Just three pi over 10. And you just keep doing it for each interval, so you'll have pilot two. Oh, I'm sorry. We got to write the function of X function pile to 10. What's the function of three Pile turn. What's the function of fly over to what's the function of seven pi over 10. What's the function of nine pi over time? All right. And then you would say, Well, what would be my function of pirate tent? So your function of X is actually this here, the sine of X. So you're going to say that you're gonna plug in that value for X and solve for that sign of X, You plug in pi over 10 4 sine of X, solve for it, and then software it with three pi over 10 pi over 27 pi over 10 and a 9.5 10. You would add those values altogether multiplied by your pie over five, and your value should come out to be 193 we 766 All right, now, looking at the remainder of this question, you see that it asks us to solve for it for when N is equal to 10 15, 100. That would be a lot of sub intervals for us to do by hand, so we would essentially plug it into a computer. And when you go ahead and plug it into either your calculator or your computer software, which everyone you're using to have that one N is equal to 10. You have 1.98 women. Summers, you could say 1.9835 to 4. When you plug in 50 you get 1.99 342 And finally, when we plug in 100 we'll get the value. 199836 2.999836 All right, And then, finally, the last part of the question is asking us, what value do these numbers appear to be approaching? And we can see that they're all approaching what looks like to be, too. It's a final answer is approximately. All right, Well, I hope that clarifies the question there. Thank you so much for watching

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Video Thumbnail

40:35

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In mathematics, integration is one of the two main operations of calculus, with its inverse operation, differentiation, being the other. Given a function of a real variable (often called "the integrand"), an antiderivative is a function whose derivative is the given function. The area under a real-valued function of a real variable is the integral of the function, provided it is defined on a closed interval around a given point. It is a basic result of calculus that an antiderivative always exists, and is equal to the original function evaluated at the upper limit of integration.

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