00:01
Okay, so we have this initial value problem.
00:06
Second derivative is 2 over x plus root x, y of 1 is 0, and y prime of 1 is 0.
00:16
So again, i'm basically just going to tell you what a computer algebra system will tell you.
00:24
And actually, you can do this without a computer algebra system when you learn a little bit more calculus.
00:29
But we know that an antiderivative of 1 over x is going to be log absolute value of x, and then an antiderivative over root x.
00:42
It's just going to be 2 thirds, x to the 3 halves, plus some constant c.
00:50
If we plug in 1, we get 0.
00:53
So a natural log of 1 is 0.
00:57
So this is just going to be two -thirds plus c...