00:01
Okay, what we want to do is we want to use a definite integral to find the area.
00:13
And the area is bounded between the graph of y equal to x over 2 plus 1 and the x axis on the interval from 0 to b.
00:25
And so we know this is the integral from 0 to b of x over 2 plus 1 dx, which any time we have addition.
00:35
Of subtraction, we're going to break them into two separate.
00:38
So i have a one -half times the integral from 0 to b of x dx, plus the integral from 0 to 1 of 0 to b of just 1 times dx.
00:51
Okay, and we know that these can be replaced with the limit.
00:57
So it's 1 half.
00:59
The limit as the partition of the rectangles goes to 0.
01:03
Of the sum, k equal to 1 to n of c sub k delta x of k plus the limit as the partitions go to 0 of the sum k equal 1 to n of here i just have a d x so this is just going to be a delta x sub k.
01:35
Okay, so now we need to define what delta x of k is and cc is.
01:43
So delta x of k is the width of each of those rectangles.
01:49
So typically it's defined to be b minus a over n.
01:53
So in our case it's just going to be b over in.
01:57
And c of k is the right endpoint or the right in point height of each of those rectangles, which is going to be a plus k times delta x sub k.
02:13
So this is going to be kb over n.
02:16
Okay.
02:17
So these limits now become the one half, the limit as n goes to infinity this time.
02:25
So i've changed those on you.
02:27
So saying that the partitions go to zero, it's the same thing as saying the number of the rectangles increases...