Question
Use a graphing utility to graph the first 10 terms of the sequence. (Assume that $n$ begins with 1 .)$$a_{n}=16(-0.5)^{n-1}$$
Step 1
a_1 = 16(-0.5)^(1-1) = 16(1) = 16 a_2 = 16(-0.5)^(2-1) = 16(-0.5) = -8 a_3 = 16(-0.5)^(3-1) = 16(0.25) = 4 a_4 = 16(-0.5)^(4-1) = 16(-0.125) = -2 a_5 = 16(-0.5)^(5-1) = 16(0.0625) = 1 a_6 = 16(-0.5)^(6-1) = 16(-0.03125) = -0.5 a_7 = 16(-0.5)^(7-1) = 16(0.015625) Show more…
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