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Use a property of determinants to show that $A$ and $A^{T}$ have the same characteristic polynomial.

see the proof

Calculus 3

Chapter 5

Eigenvalues and Eigenvectors

Section 2

The Characteristic Equation

Vectors

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Okay, so it's that determine it's a minus for them that I and take the transpose of inside do get terminates of a minus Lambda I transpose. What does that give me? That gives me determinants of a transpose minus lambda I currents pose, but I transposed in this eye so they get the 10 minutes of 80 is minus. Sam, don't buy.

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