00:01
Here we got this system of linear equations and in order to solve this system we need to pass this into the matrix form.
00:09
So that means that here we got the matrix 5 minus 2, 2, 2, 2, 2, minus 3, 1, minus 7 and 7.
00:22
So this matrix corresponds to the coefficients that are multiplying to the unknowns on the system of linear equations.
00:28
Here this vector we're going to multiply by the unknowns, so x, y and z, and this is equal to this vector of constants to 3 and minus 4.
00:40
So you can observe that here we got a linear system that is composed by the matrix a, a vector of unknown x, and these are equal, this multiplication is equal to this vector v of constants.
00:54
So what we know is that this kind of linear system, we can solve them if we use this formula that is that x is equal to the inverse of this matrix a if exists, of course, times the vector v.
01:13
So what we need is the inverse of this matrix...