00:01
So in this question, we are asked to calculate the range of wavelengths for lyman, balmer, and passion series, to show that the wavelength values do not overlap on one another, and then to show that the next series, the bracket series, overlaps with the passion series.
00:26
So in general, the wavelength is given by this formula.
00:30
1 over lambda equals r 1 over n prime is squared minus 1 over n squared where n is greater than n prime and r is 0 .0010 sorry 0 .110 110 nanometer inverse.
01:01
Now first going to lyman series.
01:13
So lyman series has n prime equals 1.
01:20
Also, n would be 2 for lambda max and n would be infinity for lambda min.
01:36
So plugging these values of n for lambda max and lambda min, we get that the minimum wavelength lambda min is 90 .91 nanometers and lambda max is 121 .21 nanometers.
02:04
So these are the minimum and maximum wavelengths for the lyman series.
02:11
Similarly for balmer series n prime equals to 2 and n would be 3 for lambda max and n would be infinity for lambda min so once again plugging it in the formula and doing the calculation lambda min comes out to be 363 .64 nanometers and lambda max comes out to be 654 .54 nanometers...