Question
use algebra to find the limit exactly.$$\lim _{x \rightarrow 1} \frac{x^{2}+4 x-5}{x-1}$$
Step 1
The expression $x^{2}+4x-5$ can be factored into $(x-1)(x+5)$. So, the given expression becomes: $$\lim _{x \rightarrow 1} \frac{(x-1)(x+5)}{x-1}$$ Show more…
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