Use an appropriate Fourier integral transform to solve the given boundary-value problem. Make assumptions about boundedness where necessary.
Use the result $\int_{0}^{\infty} \frac{\sin \alpha x}{\alpha} d \alpha=\frac{\pi}{2}, x>0$, to show that the
solution in Problem 3 can be written as
$$
u(x, t)=u_{0}-\frac{2 u_{0}}{\pi} \int_{0}^{\infty} \frac{\sin \alpha x}{\alpha} e^{-k \alpha^{2} t} d \alpha
$$