00:01
We're going to use an augmented matrix to find the solutions of the systems of equation.
00:06
So we have x plus y plus z equals 1.
00:11
We have y minus 3z equals 4, and then we have x minus z equals 2.
00:20
So since we don't have any xes on the second one, we're just going to be a 0x, and we don't have any ys here, so we have a 0 y.
00:27
Now let's make a system out of this, i mean a matrix out of this.
00:32
So i have 1 -0 -1, 1 -1 -1 -0, 1 -9 -1 -9 -1 -9 -1 -9 -1, and then i have 1 -4 -2.
00:47
Okay, first let's get rid of this 1 at the bottom and change that into 0.
00:53
So i can multiply my row 1 by negative 1, add it to row 3, and that will replace my row 3.
01:06
Okay, so once i do that, my rows 1 and 2 will stay the same.
01:12
So i have 1 -1 -1 -0 -1 -9 -3 -4.
01:21
This will end up being a 0.
01:24
And then i have negative 1 plus 3, that's a negative 1 right here.
01:32
And then i'll have negative 1 plus negative 1, which is a negative 2.
01:39
And then i'll have negative 1 plus 2 is a 1...