0:00
Hello.
00:01
So here we have the integral of x divided by the square root of 9 minus x squared.
00:07
So what we're going to do here is going to let x be equal to three times sine of theta.
00:15
And then where we have theta between negative pi over two and pi over two, then if x is equal to three sine of theta, we get that dx then is going to be equal to three times k.
00:30
Cosine theta d theta.
00:33
Okay, so then we have that the square root of 9 minus x squared.
00:44
Well, that's going to be equal to the square root of 9 and then minus 3 times sine of theta all squared.
00:53
It's going to give us a 9 minus 9 times sine squared theta.
00:58
We can then factor this out, right? and you pull out the square of nine is three.
01:04
So this is going to be equal to three times the square root of one minus sine square theta...