We set $y=0$ and solve for $x$:
$$0=\sqrt{9x^{2}-4}$$
Squaring both sides, we get:
$$0=9x^{2}-4$$
Solving for $x^{2}$, we get:
$$x^{2}=\frac{4}{9}$$
Taking the square root of both sides, we get:
$$x=\pm\frac{2}{3}$$
So, the x-intercepts of the function are
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