0:00
All right, guys.
00:01
So for this problem, we can use any method.
00:03
That's the graphing method, elimination method, or substitution method to solve the system of linear equations.
00:11
So we have 0 .02x plus 0 .05y is equal to 1 .25 and negative 0 .06x minus 0 .05 .5 .5 .5.
00:23
It's equal to 1 .05 .5.
00:23
And negative 0 .066x minus 0 .0 .5 .5 .5.
00:30
Y is equal to negative 3 .75.
00:37
So i'm going to do the elimination method.
00:40
So therefore, i'm going to figure out which variable i want to eliminate or cancel out first.
00:47
And i'm going to do that by first multiplying my first equation by three.
00:54
So therefore, that will give me 0 .06x plus, 0 .56x plus 0 .5 .5 .5.
01:02
Y is equal to 3 .75.
01:10
And for my second equation, i'm just going to rewrite that.
01:13
So negative 0 .06x minus 0 .15y is equal to negative 3 .75...