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Use Balmer's formula to calculate (a) the wavelength, (b) the frequency, and (c) the photon energy for the $\mathrm{H}_{y}$ line of the Balmer series for hydrogen.

a. $434 \mathrm{nm}$

b. $6.91 \times 10^{14} \mathrm{Hz}$

c. $E=4.58\times10^{-19}J = 2.86 \mathrm{eV}$

Atomic Physics

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Cornell University

University of Washington

Simon Fraser University

University of Winnipeg

So what I have over here is the bomber Siri's From there it was already bombers formula which relates to us the way flank for a full 20 m by a certain transition. Indeed. Bomber suits. So we transition particle looking at IHS the H comma transition. And this is the foot transition. So we have hit shellfire, be tying his comma modesty, transition for what? With Siri's. And that would be from any goes to five Don't too many close to two. So we're gonna use and goes to five for this former wish here In order to find he we think for the frequency definitely fall tone that's being meted. So you have aren't one of two square minus one over five square simply fired to be about one over 100. So we think it's just 100 but by 21 times the right, But constant are she gets full point tree full. I'm Stan triple minus seven. It is just 44 nanometers. Notify the frequency. Can you see over Lambda Safety speed of flight. You get about 6.91 time sent for 14 huts and finally to get the energy. Do you fault on energy user equals to HF you get energy about 4.5 it, stan por minus 19 juice. I've got to convert this into electron votes. You can do so by dividing by 1.6 time state, about minus 19 juice for evey to get in terms off electron volts about 2.86 even.

National University of Singapore

Atomic Physics