Question
Use basic integration formulas to compute the following antiderivatives. $$\int_{0}^{\pi / 2}(x-\sin x) d x$$
Step 1
The antiderivative of $x$ is $\frac{x^{2}}{2}$ and the antiderivative of $-\sin x$ is $\cos x$. So, the antiderivative of the function inside the integral is $\frac{x^{2}}{2} - \cos x$. Show more…
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