00:01
So we want to prove that this function here, f of x equals x to the third plus a x squared plus bx plus c is always increasing under the condition that b is greater than a squared over three.
00:20
So the first thing we want to do is we know that when a derivative is positive, its original function is going to be increasing.
00:32
So we can use that to, we can prove that the derivative of f of x is always positive.
00:39
So first we want to take the derivative, so we have 3x squared plus 2 a x plus b, and the derivative of a constant is just 0.
00:51
And first we can factor out the 3, leaving us with 3 times x squared plus 2 thirds a x plus b over 3.
01:02
And now we can actually use a complete the square method.
01:09
So if we have x plus a over 3 squared, we have b over 3 left over, and then we want to subtract a squared over 9, which came from completing the square...