Question
Use composition of functions to show that $f^{-1}$ is as given.$$f(x)=\frac{7}{8} x, f^{-1}(x)=\frac{8}{7} x$$
Step 1
This means we replace $x$ in $f(x)$ with $f^{-1}(x)$. So, $f(f^{-1}(x))=f\left(\frac{8}{7} x\right)=\frac{7}{8} \cdot \frac{8}{7} x$. Show more…
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