Use convolution to show that if $X$ and $Y$ are independent exponential random variables with parameters $\alpha$ and $\beta$, respectively, where $\alpha \neq \beta$, then the density function $f$ of their sum $X+Y$ is given by
$$
f_{X+Y}(t)=\frac{\alpha \beta}{\alpha-\beta}\left(e^{-\beta t}-e^{-\alpha t}\right), \quad t \geq 0 .
$$
[We showed this, using the Laplace-Stieltjes transform, in Example 3.4.1.]