00:01
Okay, so for this problem, you're given the reaction, and you want to show the curved arrows that denote electron movement.
00:11
So what you really want to make sure of is that when you're drawing electrons, you go from a high electron density to low electron density.
00:28
Because your arrows show movement of electrons.
00:40
So for this first example, you have your hydroxide is going to, the two electrons on your hydroxide are going to form a new bond between the oxygen and hydrogen, and then the electrons from the sigma bond are going to be pushed onto this oxygen.
01:03
So this oxygen here has a lone pair of electrons, giving it a negative charge, and this hydroxide forms water.
01:17
In part b, our pie bond is now our source of electrons.
01:25
So the electrons from our pie bond are going to form a new bond between this carbon and bromine.
01:33
And then because this carbon here doesn't have a full octet, it has a positive...