Question
Use curved arrows to show the movement of electrons in the following reaction steps. (Hint: Look at the reactants and look at the products and then draw the arrows to convert the reactants to products.)SOLUTION TO 15 a. From the products we see that the doubly bonded oxygen gains a proton and $\mathrm{H}_{3} \mathrm{O}^{+}$ loses a proton with oxygen retaining the electrons it shared with the proton. Now we need to draw the arrows that result in those products. Notice that the oxygen that gained a proton became positively charged and that the oxygen that lost a proton is no longer positively charged.
Step 1
The nucleophile is the species that donates electrons and the electrophile is the species that accepts electrons. In this case, the nucleophile is the doubly bonded oxygen and the electrophile is the $\mathrm{H}_{3} \mathrm{O}^{+}$. Show more…
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Add curved arrows to the reactants to indicate the movement of electrons in this reaction. Draw the reaction products as skeletal structures (do NOT show hydrogens on carbons and do NOT show lone pair electrons). If a heteroatom–hydrogen bond is present, add the hydrogen by using the arrow hydrogen key. Show any formal charges on the products that are not zero. Add curved arrows.
Draw curved arrows to show the flow of electrons responsible for the conversion of the reactants into the products:
Draw curved arrows to show the flow of electrons responsible for the conversion of the following reactants into products:
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