00:02
Okay, let's help number 45 where we know is history energy dltgmot is the mission of formation, energy of products, minus energy of formation of the reactant.
00:15
This is the first reaction in reason.
00:18
So we need to balance it.
00:21
So i'm going to put two here and here.
00:27
And also from that, we have found out the formation of h2.
00:35
And remember they're all in gas phone so we need to find accordingly so h2 is minus 228 .6 fluorine is 0 it's 0 is minus 95 .3 and o2 is 0 so it will be summation of product that is 2 22 minus 22 minus 220 8 .6 to o plus 2 .0 now i need to put another 2 over here so 2 in 2 minus 228 .6 plus 2 into fellow fluorine is 0 minus the reactant which is 4 hcl below 0 minus 905 .3 plus photo zero to calculation in response minus 76 kilojouca now we need to find delta g note which is minus r t natural law of k so we can write it this delta g node right r t we need to find k which is a glyph constant so k is opposed to a lock inverse minus delta gnaut by r t after substituting all the values the value of k becomes 2 into the part 3 now let's find out equation b which is f a 2 o3 h2 in gas form f e 3 -04 with solid form and h2o.
04:04
I'm spelling this one.
04:06
So we need to put a 2 over here.
04:15
So if you should be 6, so it's another 3.
04:22
You know what delta g is.
04:26
Submission of the products, which is 2 into minus...