00:01
Okay, we have two parts of this question.
00:06
So, starting with part a.
00:09
The reaction is 2 co plus o2.
00:14
It gives out 2 co2.
00:18
Calculating the gif free energy.
00:21
So change in gips free energy is the gips free energy of product minus the gif free energy of reactant.
00:32
Substituting those form substituting the values into the formula we have two mole of carbon monoxide so two multiplied with the gives free energy of carbon monoxide which is negative 394 .4 we have that's it or sorry we have two moles of carbon dioxide so this goes here minus two moves of carbon monoxide so two multiplied with gibbs free energy of carbon monoxide that is negative 137 .2 plus one mole of oxygen gives free energy zero sorry and the answer over here is negative 514 .4 kilojoules.
01:34
Under non -standard conditions, the formula change in gibbs free energy of the reaction g0 of reaction plus rt natural lock.
01:52
At equilibrium, the value of q will be equal to k and g0 of the reaction will be equal to 0...