00:01
We have three equations and we're going to be calculating k, the equilibrium constant, for each one of them.
00:07
Let's begin.
00:09
Our first equation.
00:14
Once again, we're using the data in appendix c.
00:24
How does that look beautiful? so i'm going to write a little bit more out for the first one than i am the second.
00:34
For subsequent, this will equal the summation of my delta, my give, my free energies.
00:45
My products minus reactants.
01:03
So we can substitute our values into this.
01:22
And this is 1 .30 kilojoules per mole.
01:28
That's my products and then my reactants are this is zero.
01:41
And this one isn't zero.
01:43
This one's 19 .37.
01:53
And that's kilojoules.
02:04
I'm going to leave that off there.
02:05
So my answer for this is negative 16 .7 kilojoules.
02:13
Next, we're going to use this equation to solve for the k .e .q.
02:28
So rearranging for this, our equilibrium constant will be this equation.
02:40
And now we can plug our values in here.
02:54
I'm going to change this one to jules, foot matches.
03:00
It would be 1 .6 .0.
03:02
I guess i won't do it that way.
03:04
I'm just going to go 16 .77 times 10 to the third joules divided by my r.
03:14
I'm going to leave my units off, my r, i just can't be times 298 and that's killed.
03:23
So my k -eq for this one will be equal to 869.
03:28
57, which will be about 870 right there.
03:42
Okay, number one, done.
03:45
Now let's do number two.
03:47
Is there a equate, or beat, i should say.
04:08
I'm going to go take a look at this equation.
04:14
I should have had a double arrow on my last one too.
04:17
I did.
04:18
Okay.
04:20
Okay, there we go.
04:21
So, very nice...