00:01
Okay, so in this one, we have a central density of the sun, we have a mean opacity, and for part a, we want to find the mean free path.
00:15
Well, this one is pretty easy because the mean free path, l equals one over your average kappa times row.
00:23
So in this case, it would just be one divided by 0 .217 times 1 .5 times 10 to the 5th, giving an answer of, of 3 times 10 to the negative 5 meters.
00:37
Okay, what about b? we want to find the average time it would take for the photon to escape from the sun if the mean free path remained constant.
00:48
Well, the first thing you want to start out with is the number of random walks, sized steps, or steps needed.
01:06
And to do this, you're going to say that n equals d over l squared...