00:01
This question asks you to use descartes's rule of signs to determine the possible number of positive and negative real zeros for a given function.
00:10
That given function is f of x equals x to the fifth minus x to the fourth plus x cubed minus x squared plus x minus eight.
00:35
So let's go ahead and take a look or analyze f of x to see how many sign changes there are.
00:44
Of course, this is positive.
00:46
So we have one, two, three, four, five.
00:55
Okay.
00:57
So let's record that.
00:59
What that means is that if we are comparing the number of possible and negative real roots, it's possible that we have let's say these are our possible positives possible negatives and possible complex or imaginary we have a possible five positive real zeros we'll continue to build that chart in a minute well we've got a possible five we can do this part a possible five possible three or a possible one i didn't mean to write a two and we can complete this chart in a couple of minutes.
01:44
Let's now inspect f of negative x, substituting in a negative x, wherever we see x, and then going ahead and simplifying all of this.
02:24
I just want to double check that i did this correctly.
02:26
So i had an odd and it changed, even it stayed the same.
02:30
The odd changed.
02:31
The even stayed the same.
02:33
Odd change, evens stayed the same.
02:34
So now when we go through when we are looking for sign changes, there are none.
02:40
So that means that there are zero possible negative real zeros.
02:48
So if that is the case, then if we did have five real positive or positive real zeros, we would have zero negative and zero imaginary.
03:00
If we had three, we would have two imaginary roots or zeros...