Use drawings to explain how an enzyme (such as hexokinase, mentioned in the text) can distinguish its normal substrate (here D-glucose) from the optical isomer L-glucose, which is not a substrate. (Hint: remembering that a carbon atom forms four single bonds that are tetrahedrally arranged and that the optical isomers are mirror images of each other around such a bond, draw the substrate as a simple tetrahedron with four different corners and then draw its mirror image. Using this drawing. indicate why only one optical isomer might bind to a schematic active site of an enzyme.)