00:01
So first of all we need to find the cross -sectional area here.
00:06
We know this area here will be i equal to pi r square, so r will be from here to here.
00:13
And here will be the value of the x, which is the square of y, so equal to by y.
00:20
And then, and that's will be the a of y.
00:25
And with by formula, we have dy over dt, equal to b.
00:31
Equals 0 .0 .0 5 times square, time y, equal to minus square root of 2g times y, dividing by a y.
00:44
So this one can be simplified by y.
00:48
So this one can be simplified by minus 0 .0 .05 times squared of 2g, square, j squared by 2, g...