00:01
All right, so we have to calculate the length of the curve using ces, okay, computer algebra system.
00:10
And the curve given to us is essentially y is equals to x x x to par 4 by 3.
00:27
Well, x is from 0 to 1.
00:33
Okay, so let's press get its first derivative.
00:36
So first derivative here is so differentiate this curve.
00:39
So what we'll be getting is y -dice and that will be 4 by 3 x x.
00:43
To par 1 by 3.
00:45
So that is the first derivative of it or differentiation of it.
00:49
So let's calculate the length of this curve.
00:51
So formula for that is essentially integration 0 to 1, root hour 1 plus plus derivative whole square of this.
01:00
So that will be actually 16 by 9 x x to par 2x2 by 3 into d of x.
01:08
Okay.
01:09
So now in the question they have given us that we have calculated using substitution.
01:14
So let's do the substitution.
01:16
So let, so we have to calculate this integral, okay? so we are doing substitution.
01:23
So let x is equal to u cube.
01:30
So if we differentiate it, so what will be getting? so we'll be getting d x will be equals to 3 u square into d u.
01:38
So our integral, so the l will become essentially.
01:41
And so you can clearly see the lower limits.
01:43
So if i put x equals to 0, you will also be 0.
01:46
If i put x is equals to 1, you will also be 1.
01:48
So the limits of the integral will remain the same.
01:51
So 0 to 1...