00:03
Now we are given a lower triangular n by n matrix with non -zero entries on the diagonal, and we're asked to show that this matrix is invertible and that its inverse is also lower triangular.
00:20
So let a be a lower triangular matrix with non -zero entries on the diagonal.
00:46
This is going to be an n -by -n matrix.
00:48
Now consider the augmented matrix a -i, where i is the n -by -n identity matrix? well, first we have that the 1 -1 entry can be scaled to 1, so we'll do this, and then we have that the entries below this entry can be changed to 0.
02:14
By adding multiples of row 1 to each row below it, now this affects only the first column.
02:38
Of a in the first column of i.
03:15
So the 2 -2 entry in the new matrix is still non -zero, and it is the only non -zero entry of row 2 in the first n columns.
04:29
This is because, once again, a was lower triangular...