00:03
In this problem, we are asked to find the indicators of the following titrations.
00:10
In part a, we know that this is a titration between a weak base and a strong acid.
00:18
And in a titration between a weak base and a strong acid, the equivalence point will have a ph that is greater than 7.
00:28
We will need to construct an ice table.
00:31
We will first write out our chemical equation for this reaction.
00:41
Since both the base and acid are solutions in one liter, our number of moles would be 0 .5 moles for both the base and the acid.
01:01
So this is where we will start off.
01:04
And at the equivalence point the number of moles for the acid and the number of moles for the base should be equal to each other next we will minus both sides by 0 .5 moles because this is the number of moles that will go under reaction and we will find our final number of moles for this reaction next we will need to find the molarity of ch3 and h2.
01:46
Now because for the base and acid, they both are constituted of 1 liter.
01:55
So in addition, or the sum of the acid and the base will give us 2 liters.
02:01
So to solve for the malarity, we will have 0 .5 moles over 2 liters, which gives us 0 .25 molars.
02:16
Next, we will do another ice table for the strong acid.
02:29
In this, we will solve for the concentration of h -30 plus to solve for our ph value, which will help us indicate what our indicator is...