Use Formula 10 to evaluate each logarithm correct to six decimal places.
(a) $ \log_5 10 $
(b) $ \log_3 57 $
for this problem. We're going to use the change of based formula to convert each of these algorithms into natural log. And then we can compute it with a calculator So long based five of 10 converts into the natural log of 10 divided by the natural log of five. When you put that in the calculator to six decimal places, you get 1.430677 Similarly, for part B, when we use the change of based formula, we get the natural log of 57 divided by the natural log of three. And when we put that in the calculator to six decimal places, we get 3.680 144