Question
Use Green’s Theorem to evaluate the integral. In each exercise, assume that the curve C is oriented counterclockwise.$\oint_{C} \ln (1+y) d x-\frac{x y}{1+y} d y,$ where $C$ is the triangle with vertices $(0,0),(2,0),$ and $(0,4)$
Step 1
We can use the formula for the slope of a line, which is $m = \frac{y_2 - y_1}{x_2 - x_1}$. Substituting the given points into this formula, we get $m = \frac{4 - 0}{0 - 2} = -2$. So, the equation of the line is $y = -2x + 4$. Show more…
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Use Green's Theorem to evaluate the integral. In each exercise, assume that the curve $C$ is oriented counterclockwise.$\oint_{C} \ln (1+y) d x-\frac{x y}{1+y} d y$, where $C$ is the triangle with vertices $(0,0),(2,0)$, and $(0,4)$.
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Use Green's Theorem to evaluate the integral. In each exercise, assume that the curve $C$ is oriented counterclockwise.$$ \begin{aligned} &\oint_{C} \tan ^{-1} y d x-\frac{y^{2} x}{1+y^{2}} d y, \text { where } C \text { is the square with }\\ &\text { vertices }(0,0),(1,0),(1,1), \text { and }(0,1) \end{aligned} $$
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