00:01
For this problem, we are asked to find, or to use green's theorem to find the area of the region bounded by the line x plus y equals 3, and the hyperbola xy equals 2.
00:11
So, we are trying to find the area of this region enclosed, where the red line corresponds to x plus y equals 3, and the blue line corresponds to x, y, equals 2.
00:24
Which i'll note, we can rewrite both of these as y equals 3 minus x and y equals 2.
00:31
Over x respectively so what we'll do is now keep in mind we want to do this using greens theorem explicitly what we'll do is split this apart into two different curves i'll label them c1 and c2 and then use green's theorem to find the contribution to the area by integrating along each curve so we have c1 c2 so to begin with c1 we can define and we do want to be if uh if uh you for no reason other than consistency, let's go counterclockwise here.
01:07
That is the standard for greens theorem to make sure everything works out properly.
01:10
Let's say that we have x equals well it starts at 2.
01:14
So let's say x equals 2 minus t and it ends up at 1 so t is between 0 and 1.
01:21
And then we have y equals 3 minus x but x is 2 minus t so y equals 3 minus 2 minus negative t.
01:29
So 3 minus 2 plus t or y equals t plus 1, which would then give us that dx equals negative d t and d y equals d t.
01:40
So we have from green's theorem that the area will be equal to, in this case it's the integral from 0 to 1, or 1 half the integral from 0 to 1, of negative y d x.
01:53
So that would be negative t minus 1 times negative d t.
01:57
So just t plus 1...