Question
Use implicit differentiation to find $y^{\prime}$ and evaluate $y^{\prime}$ at the indicated point.$$x e^{y}-y=x^{2}-2 ;(2,0)$$
Step 1
The derivative of $x e^{y}$ is $e^{y} + x e^{y} y^{\prime}$ and the derivative of $y$ is $y^{\prime}$. The derivative of $x^{2}$ is $2x$ and the derivative of $-2$ is $0$. So we get: $$e^{y} + x e^{y} y^{\prime} - y^{\prime} = 2x$$ Show more…
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