Question
Use integration by parts to obtain the formula$\int \sqrt{1-x^{2}} d x=\frac{1}{2} x \sqrt{1-x^{2}}+\frac{1}{2} \int \frac{1}{\sqrt{1-x^{2}}} d x$
Step 1
We want to integrate \(\int \sqrt{1-x^2} \, dx\). Choose \(u = \sqrt{1-x^2}\) and \(dv = dx\). Show more…
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