00:01
In this question, we have the vertices of a figure that is 2.
00:07
Minus 3, 4 .6 and 6 .1.
00:16
We are required to find the area of this figure.
00:20
So let's see how to solve this question.
00:22
First of all, let's mark these coordinates on the graph and join them to get the desired figure.
00:31
And the figure is shown below.
00:32
So, this is a desired figure.
00:36
And now, let's find the equation of line for the points 2.
00:44
Minus 3 and 4 .6.
00:49
We know that the standard form of equation of line can be written as y minus y1 is equals to y2 minus y1 divided by x2 minus x1 into x minus x1.
01:04
Now, substitute all the values.
01:07
So we can write y minus y1, that means minus 3.
01:13
So minus minus 3 will be equal to plus 3 is equal to y to y to minus y 1, that means 6 minus minus 3, that means 6 plus 3 divided by 4 minus 2 into x minus 2.
01:30
When we further calculate this, we get x is equal to 2.
01:36
Upon 9 into y plus 12.
01:41
So this is equation first.
01:45
Similarly, now let's find the line joining the points 2 comma minus 3 and 6 .1.
01:56
So we will have y minus 1 is equals to 1 plus 3 divided by 6 minus 2 into x minus 6...