Use isospin invariance to show that the reaction cross sections $\sigma$ must satisfy
$$
\frac{\sigma\left(\mathrm{pp} \rightarrow \pi^{+} \mathrm{d}\right)}{\sigma\left(\mathrm{np} \rightarrow \pi^0 \mathrm{~d}\right)}=2,
$$
given that the deuteron $\mathrm{d}$ has isospin $I=0$ and the $\pi$ has isospin $I=1$.