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In this video, we will be solving problem 8 from chapter 13, section 9.
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Problem 8 gives the f function as written on the screen and says that it's subject to the constraint, which is written on the right.
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We need to use the lagrange multipliers to find the minimum and maximum with this constraint in place.
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Now, the first thing is to rewrite the constraint as the g function of x and y and set it equal to zero.
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Now we can find the gradient of f and g, the gradient just being the partial derivative with respect to x and y, both functions.
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Now that we have the gradients, we can find the lagrange multiplier conditions.
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We set each partial derivative equal to each other, but multiply lambda on the g side.
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And the last condition is just the g equation as we wrote above equal to zero.
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And now we have our conditions.
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We can rewrite these equations to find the x and y values at which there could be potential minimums and maxims.
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So what we can do here is try to combine these two equations.
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We can do the same thing for this one over here.
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Note that these two equations are very similar, it's just that the x and y values are swapped.
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And now that each one is equal to lambda, the left sides of the equations can be equated.
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So essentially we can just be really...
03:36
These two values and put a giant equal sign between this equation and that equation.
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So with canceling out the two thirds, we can move the y and x values over to the other side...