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Use $\log 2=0.3010$ and $\log 5=0.6990$ and the properties of logarithms to compute the given logarithm, do not use a calculator.$$\log 16$$

$$1.204$$

Algebra

Chapter 4

Exponential and Logarithmic Functions

Section 6

Properties of Logarithmic Functions

McMaster University

Harvey Mudd College

University of Michigan - Ann Arbor

Lectures

01:24

Use $\log 2=0.3010$ and $\…

01:01

02:21

01:36

02:14

Assume that $\log 4 \appro…

00:27

01:04

00:20

Rewrite the logarithm equa…

00:24

00:25

00:21

So all we need Thio do this problems to understand that log of two is equal 2.301 eso as you look at and we don't need the log of five part of the problem. All we need is that because when I look at log of 16, we can think about that. That's equal to log of 22 times. Two times, two times two is 16. That's four twos. You can double check with the calculator. I'm sure you're not supposed to do this with the calculator that we can move this forward in front. That's using the law of logs. Yeah, and then what we can do is use substitution. That log of two is equal to this 20.301 So looking at four times 40.301 I know there's an extra zero in the end there. But that really doesn't matter. And I would just distribute because ah, that's how I do math. Like four times one is four, then four times three is 12 eso it should be 1.204 I'm double checking my work. Um, I don't need this parentheses in here anymore. I'll just circle it because that's the right answer.

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