00:01
In this question, we are asked to prove by induction the statement that said the sum of integers cube from 1 to n equals this term, n times n plus 1 over 2 square.
00:20
So we will call this statement p of n for n as some positive integers.
00:28
By using induction, we have 2.
00:31
Step to follows first the basic step is the first case that the statement holds true and in this case is when n equals to one that's not always the case that it has to start with one just that in this case one is the basic step other case may start from to five 11 depending on question so don't don't stuck on this n equal to one always okay so p of one we just substitute n as one right so on this side there will be sum of just one term and on this side we we have this number is to one square so it's one right that means p1 said 1 equals to so it's true.
01:37
Then we are clear this basic step.
01:39
Next, the inductive step.
01:41
We assume that if the statement is true for some n that we want, so it's greater or equal to one, some positive integer.
01:57
We want to show that n plus 1 is true as well.
02:00
So this hasn't happened yet.
02:04
We have to show it.
02:05
And how to show it? we can use p n as the starting point because it's like an assume statement so we have it as facts as information now consider the sum from 1 to n plus 1 cube this first n term you you can see that we can use inductive hypothesis right because it is n is up to n so p of n work.
02:42
That means we can change it into this term and the last term stay the same...