00:01
So we're going to be using mathematical induction, and the first step with mathematical induction is the base case.
00:07
And with this basis step, we let n equal 1.
00:13
So we see that we have the complement of the union from n, from k equals 1 to n.
00:24
But we're going to let n equal 1.
00:27
So it's just 1 to 1 of a sub k.
00:30
And we want to show that that's equal to the intersection from k equals 1 to n but it's just going to be 1 since we're letting an equal 1 of a sub 1 or actually a sub k well since we're just going from 1 to 1 that just tells us that we have the union of a 1 the complement of that is equal to the intersection of the complement of a1.
01:03
So this is essentially what we have.
01:08
We know that the union of just one set is itself.
01:11
So really this is the same thing as just the complement of a1.
01:16
And the intersection of just one set is just the set itself.
01:19
So it's the same as this.
01:21
So based on that, the base case is correct.
01:24
Next, we want to assume pk.
01:29
To be true.
01:32
And then we're going to want to look at k plus 1, or in this case, n plus 1...